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`0 lt x lt 3``3 lt x lt 7``-7 lt x lt -3``-7 lt x lt 3`

Answer :

BSolution :

We have, `|(5-x)a|lt|2a|` <br> `|5-x||a|lt2|a|` <br> `implies|5-x|lt2` <br> `implies-2 lt 5-x lt 2` <br> `implies 3 lt x lt `7