NTA-NET (Based on NTA-UGC) Electronic Science (Paper-II): Questions 114 - 117 of 124

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Question number: 114

» Optical Communication » Types of Fibre

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Appeared in Year: 2018

MCQ▾

Question

Following transmission media are given:

1) Twisted pair cables

2) Optical fibre cables

3) Coaxial cables

4) Microwaves

For high rate data transmission systems, arrange the above in terms of their Losses in ascending orders. (July)

Choices

Choice (4) Response

a.

4), 3), 1), 2)

b.

2), 3), 1), 4)

c.

1), 2), 3), 4)

d.

3), 2), 1), 4)

Question number: 115

» Linear Integrated Circuits and Op-Amps » Multistage Amplifiers

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Appeared in Year: 2018

Assertion-Reason▾

Question

Assertion (Ꭺ)

The total gain of a cascaded system is determined by the product of the gains of each stage. (July)

Reason (Ꭱ)

The gain of each stage must be determined under loaded conditions.

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ

b.

Both Ꭺ and Ꭱ are false

c.

Ꭺ is false but Ꭱ is true

d.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

Question number: 116

» Solid State Device and Fabrication » Electronic Transport in Semiconductor

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Appeared in Year: 2018

MCQ▾

Question

Following are the semiconductor materials having certain values of recombination co-efficients. Arrange them in terms of ascending order:

1) GaP

2) Si

3) InAs

4) GaAs

The correct sequence is: (July)

Choices

Choice (4) Response

a.

3), 2), 1), 4)

b.

1), 2), 3), 4)

c.

2), 1), 3), 4)

d.

4), 2), 1), 3)

Question number: 117

» Networks and Theorems » Nodal and Mesh Analysis

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Appeared in Year: 2018

Assertion-Reason▾

Question

Assertion (Ꭺ)

All the mesh currents are necessarily the loop currents but all the loop currents may not be the mesh current. (July)

Reason (Ꭱ)

The mesh current is the current, which flows only around the perimeter of a mesh.

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are false

b.

Ꭺ is false but Ꭱ is true

c.

Ꭺ is true but Ꭱ is false

d.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ