Mathematics [NSTSE (National Science Talent Search Exam- Unified Council) Class 9]: Questions 32 - 34 of 989

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Question 32

Mathematics
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Question

MCQ▾

A diagonal of a rectangle is inclined to one side of the rectangle at . The acute angle between the diagonals is:

Choices

Choice (4)Response

a.

b.

c.

d.

Question 33

Mathematics
Edit

Question

MCQ▾

Triangle PQR is inscribed in a circle. If then PR is equal to

Triangle poly1Triangle poly1: Polygon P, R, QCircle cCircle c: Circle through B_1 with center C_1Arc dArc d: Semicircle through D and EArc eArc e: Semicircle through A and BSegment c_1Segment c_1: Segment [P, R] of Triangle poly1Segment aSegment a: Segment [R, Q] of Triangle poly1Segment bSegment b: Segment [Q, P] of Triangle poly1Point PPoint P: Point on cPoint PPoint P: Point on cPoint PPoint P: Point on cPoint RPoint R: Point on cPoint RPoint R: Point on cPoint RPoint R: Point on cPoint QPoint Q: Point on cPoint QPoint Q: Point on cPoint QPoint Q: Point on cXâ°text1 = “Xâ°”Xâ°text1_2 = “Xâ°”

Image of a Triangle PQR That is Inscribed in a Circle

Choices

Choice (4)Response

a.

22.4 cm

b.

5.6 cm

c.

Cannot be determined from given data

d.

11.2 cm

Question 34

Mathematics
Edit

Question

MCQ▾

In the adjoining figure, BO, CO are angle bisectors of external angles of . Then is

Triangle poly1Triangle poly1: Polygon A, B, CTriangle poly2Triangle poly2: Polygon B, O, CArc eArc e: Semicircle through J and KArc fArc f: Semicircle through L and MSegment cSegment c: Segment [A, B] of Triangle poly1Segment aSegment a: Segment [B, C] of Triangle poly1Segment bSegment b: Segment [C, A] of Triangle poly1Segment c_1Segment c_1: Segment [B, O] of Triangle poly2Segment b_1Segment b_1: Segment [O, C] of Triangle poly2Segment dSegment d: Segment [C, B] of Triangle poly2Segment gSegment g: Segment [B, P] Segment hSegment h: Segment [C, Q] Point AA = (0.2,2.08) Point AA = (0.2,2.08) Point AA = (0.2,2.08) Point BB = (-1.96, -0.94) Point BB = (-1.96, -0.94) Point BB = (-1.96, -0.94) Point CC = (2.18, -0.98) Point CC = (2.18, -0.98) Point CC = (2.18, -0.98) Point OO = (0.1, -3.1) Point OO = (0.1, -3.1) Point OO = (0.1, -3.1) Point PP = (-3.14, -2.68) Point PP = (-3.14, -2.68) Point PP = (-3.14, -2.68) Point QQ = (3.2, -2.54) Point QQ = (3.2, -2.54) Point QQ = (3.2, -2.54) 1text1 = “1”2text1_1 = “2”3text1_2 = “3”4text1_3 = “4”

Image of Triangle ABC with Another Triangle BOC in It

Choices

Choice (4)Response

a.

b.

c.

d.