NSTSE (National Science Talent Search Exam- Unified Council) Class 9: Questions 327 - 328 of 2000

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Question number: 327

» Mathematics » Triangles

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An exterior angle of a triangle is and one of the interior of opposite angles is . Then the other two angles of a triangle are

Triangle poly1Triangle poly1: Polygon A, B, CArc eArc e: Semicircle through K and LArc dArc d: Semicircle through I and MSegment cSegment c: Segment [A, B] of Triangle poly1Segment aSegment a: Segment [B, C] of Triangle poly1Segment bSegment b: Segment [C, A] of Triangle poly1Segment fSegment f: Segment [A, H] Point AA = (0.72,3.44) Point AA = (0.72,3.44) Point AA = (0.72,3.44) Point BB = (-1.8,0.26) Point BB = (-1.8,0.26) Point BB = (-1.8,0.26) Point CC = (2.74,0.26) Point CC = (2.74,0.26) Point CC = (2.74,0.26) 65â°text1 = “65â°”120â°text1_1 = “120â°”

Image of a Triangle Having 120 Degree of Exterior Angle

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Choice (4)Response

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Question number: 328

» Mathematics » Quadrilaterals

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In the given figure PO and SO are the bisectors of and of the quadrilateral PQRS. Then the is

Quadrilateral poly1Quadrilateral poly1: Polygon P, Q, R, SArc eArc e: Semicircle through G and HArc hArc h: Semicircle through I and JSegment aSegment a: Segment [P, Q] of Quadrilateral poly1Segment bSegment b: Segment [Q, R] of Quadrilateral poly1Segment cSegment c: Segment [R, S] of Quadrilateral poly1Segment dSegment d: Segment [S, P] of Quadrilateral poly1Segment fSegment f: Segment [S, E] Segment gSegment g: Segment [P, F] Point PP = (2.73,1.62) Point PP = (2.73,1.62) Point PP = (2.73,1.62) Point QQ = (3,4.36) Point QQ = (3,4.36) Point QQ = (3,4.36) Point RR = (-0.75,4.29) Point RR = (-0.75,4.29) Point RR = (-0.75,4.29) Point SS = (-1.2,1.56) Point SS = (-1.2,1.56) Point SS = (-1.2,1.56) Point OPoint O: Intersection point of f, gPoint OPoint O: Intersection point of f, gPoint OPoint O: Intersection point of f, g105â°text1 = “105â°”85â°text1_1 = “85â°”

Image of a Quadrilateral PQRS

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Choice (4)Response

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