NSTSE (National Science Talent Search Exam- Unified Council) Class 9: Questions 17 - 18 of 2000

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Question number: 17

» Mathematics » Lines and Angles

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Supplement angle of

Arc c Arc c: Semicircle through D and E Segment f Segment f: Segment [A, B] Segment g Segment g: Segment [A, C] Point A A = (1.44,2.92) Point A A = (1.44,2.92) Point A A = (1.44,2.92) Point B B = (3.56,5.6) Point B B = (3.56,5.6) Point B B = (3.56,5.6) Point C C = (4.98,2.92) Point C C = (4.98,2.92) Point C C = (4.98,2.92) 67.4â° text1 = “67.4â°”

Image of an Angle of 67.4 Degrees

Representing the image of an angle of 67.4 degrees, so find its supplement angle

Choices

Choice (4) Response

a.

b.

c.

d.

Question number: 18

» Mathematics » Lines and Angles

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In the figure, AD is the bisector of of then

Triangle poly1 Triangle poly1: Polygon A, B, C Arc d Arc d: Semicircle through E and F Arc e Arc e: Semicircle through G and E Arc g Arc g: Semicircle through H and I Arc h Arc h: Semicircle through I and J Segment c Segment c: Segment [A, B] of Triangle poly1 Segment a Segment a: Segment [B, C] of Triangle poly1 Segment b Segment b: Segment [C, A] of Triangle poly1 Segment f Segment f: Segment [A, D] Point A A = (-0.8,3.06) Point A A = (-0.8,3.06) Point A A = (-0.8,3.06) Point B B = (-2.46, -0.06) Point B B = (-2.46, -0.06) Point B B = (-2.46, -0.06) Point C C = (0.84, -0.04) Point C C = (0.84, -0.04) Point C C = (0.84, -0.04) Point D Point D: Point on a Point D Point D: Point on a Point D Point D: Point on a 1 text1 = “1” 2 text1_1 = “2” 3 text1_2 = “3” 4 text1_3 = “4”

Image of a Triangle ABC in Which AD is Bisector of A

Representing the image of a triangle ABC in which AD is bisector of A

Choices

Choice (4) Response

a.

b.

c.

d.

All of the above

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