NSTSE (National Science Talent Search Exam- Unified Council) Class 9: Questions 95 - 97 of 2000

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Question number: 95

» Mathematics » Quadrilaterals

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MCQ▾

Question

In a quadrilateral ABCD, then =

Choices

Choice (4) Response

a.

b.

c.

d.

Question number: 96

» Mathematics » Lines and Angles

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Question

From the adjoining figure , then the value of is

Arc e Arc e: Semicircle through I and F Segment f Segment f: Segment [A, B] Segment g Segment g: Segment [C, D] Point A A = (-0.46,0.54) Point A A = (-0.46,0.54) Point A A = (-0.46,0.54) Point B B = (6.46,0.52) Point B B = (6.46,0.52) Point B B = (6.46,0.52) Point C Point C: Point on f Point C Point C: Point on f Point C Point C: Point on f Point D D = (3.66,3.52) Point D D = (3.66,3.52) Point D D = (3.66,3.52) 3xâ° text1 = “3xâ°” 4yâ° text1_2 = “4yâ°”

Image of Two Adjoining Angles

Representing the image of two adjoining angles making a supplementary angle

Choices

Choice (4) Response

a.

b.

c.

d.

Question number: 97

» Mathematics » Triangles

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In the figure given below, find .

Triangle poly1 Triangle poly1: Polygon A, B, C Arc d Arc d: Semicircle through F and G Arc e Arc e: Semicircle through H and I Arc h Arc h: Semicircle through J and K Arc k Arc k: Semicircle through L and M Arc p Arc p: Semicircle through N and O Segment c Segment c: Segment [A, B] of Triangle poly1 Segment a Segment a: Segment [B, C] of Triangle poly1 Segment b Segment b: Segment [C, A] of Triangle poly1 Segment f Segment f: Segment [A, D] Segment g Segment g: Segment [B, E] Segment i Segment i: Segment [P, Q] Segment j Segment j: Segment [R, S] Segment i_1 Segment i_1: Segment [P_1, Q_1] Segment j_1 Segment j_1: Segment [R_1, S_1] Point A A = (8.94,3) Point A A = (8.94,3) Point A A = (8.94,3) Point B B = (8.22,0.4) Point B B = (8.22,0.4) Point B B = (8.22,0.4) Point C C = (13.34,0.36) Point C C = (13.34,0.36) Point C C = (13.34,0.36) Point D Point D: Point on a Point D Point D: Point on a Point D Point D: Point on a Point E E = (6,0.4) Point E E = (6,0.4) Point E E = (6,0.4) yâ° text1 = “yâ°” zâ° text1_1 = “zâ°” xâ° text1_2 = “xâ°” 15â° text1_3 = “15â°” yâ° text1_4 = “yâ°” 105â° text1_5 = “105â°”

Image of a Triangle ABC with a Bisector AD and Exterior Angle 105

Showing an image of a triangle ABC with a bisector AD and exterior angle 105

Choices

Choice (4) Response

a.

b.

c.

d.

All of the above

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