NSTSE (National Science Talent Search Exam- Unified Council) Class 4: Questions 1272 - 1272 of 1971

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Question number: 1272

» Mathematics » Perimeter and Area

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Question

Diagram (i) and (ii) show two identical rectangles X and Y which are arranged differently.

Quadrilateral poly1 Quadrilateral poly1: Polygon A, B, C, D Quadrilateral poly2 Quadrilateral poly2: Polygon G, H, I, J Segment a Segment a: Segment [A, B] of Quadrilateral poly1 Segment b Segment b: Segment [B, C] of Quadrilateral poly1 Segment c Segment c: Segment [C, D] of Quadrilateral poly1 Segment d Segment d: Segment [D, A] of Quadrilateral poly1 Segment f Segment f: Segment [E, F] Segment g Segment g: Segment [G, H] of Quadrilateral poly2 Segment h Segment h: Segment [H, I] of Quadrilateral poly2 Segment i Segment i: Segment [I, J] of Quadrilateral poly2 Segment j Segment j: Segment [J, G] of Quadrilateral poly2 Segment k Segment k: Segment [K, L] Segment l Segment l: Segment [M, N] Segment m Segment m: Segment [O, P] Segment n Segment n: Segment [Q, R] Segment p Segment p: Segment [S, T] Point M M = (-1.88,4.76) Point M M = (-1.88,4.76) Point N N = (3.42,4.76) Point N N = (3.42,4.76) Point O O = (-2.42,4.28) Point O O = (-2.42,4.28) Point P P = (-2.42,2.76) Point P P = (-2.42,2.76) Point Q Q = (-0.52,1.52) Point Q Q = (-0.52,1.52) Point R R = (2.74,1.52) Point R R = (2.74,1.52) Point S S = (-1.24,1.12) Point S S = (-1.24,1.12) Point T T = (-1.24, -1.98) Point T T = (-1.24, -1.98) (i) text1 = ” (i) “ (ii) text1_1 = ” (ii) “ 3 cm text1_2 = “3 cm” 7 cm text1_3 = “7 cm” 6 cm text1_4 = “6 cm” 14 cm text1_5 = “14 cm” X text1_6 = “X” Y text1_7 = “Y” X text1_8 = “X” Y text1_9 = “Y”

This Figure Shows Two Rectangles X and Y

In these rectangles arranged differently

What is the difference in perimeter between diagrams (i) and (ii)?

Choices

Choice (4) Response

a.

5 cm

b.

8 cm

c.

7 cm

d.

10 cm

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