# Wave Optics-Diffraction Due to a Single Slit Width of Central Maximum [NEET (NTA)-National Eligibility cum Entrance Test (Medical) Physics]: Questions 1 - 4 of 20

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## Question number: 1

» Wave Optics » Diffraction Due to a Single Slit Width of Central Maximum

Edit
Assertion-Reason▾

### Assertion (Ꭺ)

If a plane glass slab is placed on the letters of different colors all the letters appear to be raised up to the same height.

### Reason (Ꭱ)

Different colors have different wavelengths.

### Choices

Choice (4)Response

a.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

b.

Ꭺ is true but Ꭱ is false

c.

Ꭺ is false but Ꭱ is true

d.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ

## Question number: 2

» Wave Optics » Diffraction Due to a Single Slit Width of Central Maximum

Edit
MCQ▾

### Question

In Fresnel diffraction, if the distance between the disc and the screen is decreased, the intensity of central bright spot will

### Choices

Choice (4)Response

a.

Remain constant

b.

decrease

c.

Increase

d.

Question does not provide sufficient data or is vague

## Question number: 3

» Wave Optics » Diffraction Due to a Single Slit Width of Central Maximum

Edit
MCQ▾

### Question

A screen is placed 2 m away from the single narrow slit. Calculate the slit width if the first minimum lies 5 mm on either side of the central maximum. Incident plane waves have a wavelength of 5000 Å.

### Choices

Choice (4)Response

a.

2 × 10 -4 cm

b.

2 × 10 -4 m

c.

2 × 10 -3 cm

d.

None of the above

## Question number: 4

» Wave Optics » Diffraction Due to a Single Slit Width of Central Maximum

Edit
MCQ▾

### Question

Two spectral line of sodium D 1 & D 2 have wavelengths of approximately 5890 Å and 5896 Å. A sodium lamp sends incident plane wave on to a slit of width 2 micrometer. A screen is located at 2 m from the slit. Find the spacing between the first maxima of two sodium lines as measured on the screen.

### Choices

Choice (4)Response

a.

9 × 10 -4

b.

10 -4 m

c.

9 × 10 4 m

d.

All of the above

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