# Magnetic Effects of Current and Magnetism-Bar Magnet [NEET (NTA)-National Eligibility cum Entrance Test (Medical) Physics]: Questions 1 - 5 of 27

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## Question number: 1

» Magnetic Effects of Current and Magnetism » Bar Magnet

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MCQ▾

### Question

A short bar magnet is placed with its north pole pointing south. The neutral point is 10 cm away from the center of the magnet. If H = 0.4 gauss, calculate magnetic moment of the magnet.

### Choices

Choice (4)Response

a.

0.2Am 2

b.

lAm 2

c.

0.1 Am 2

d.

2Am 2

## Question number: 2

» Magnetic Effects of Current and Magnetism » Bar Magnet

Edit
Assertion-Reason▾

### Assertion (Ꭺ)

We cannot think of magnetic field configuration with three poles.

### Reason (Ꭱ)

A bar magnet does not exert a torque on itself due to its own field.

### Choices

Choice (4)Response

a.

Both Ꭺ and Ꭱ are false

b.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

c.

Ꭺ is true but Ꭱ is false

d.

Ꭺ is false but Ꭱ is true

## Question number: 3

» Magnetic Effects of Current and Magnetism » Bar Magnet

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MCQ▾

### Question

A 30 cm long bar magnet is placed in the magnetic meridian with its north pole pointing south. The neutral point is obtained at a distance of 40 cm from the center of the magnet. Pole strength of the magnet is (The. horizontal component of earth’s magnetic field is 0.34 Gauss)

### Choices

Choice (4)Response

a.

15.2 Am

b.

26.7 Am

c.

16.7 Am

d.

12.7 Am

## Question number: 4

» Magnetic Effects of Current and Magnetism » Bar Magnet

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MCQ▾

### Question

At magnetic equator of earth, angle of dip is

### Choices

Choice (4)Response

a.

45°

b.

Zero

c.

90°

d.

180°

## Question number: 5

» Magnetic Effects of Current and Magnetism » Bar Magnet

Edit
MCQ▾

### Question

A bar magnet with its poles 25 cm apart and of pole strength 24.0 A-m rests with its center on a frictionless pivot. A force F is applied on the magnet at a distance of 12 cm from the pivot, so that it is held in equilibrium at an angle of 30° with respect to a magnetic field of induction 0.25 T. The value of force F is

### Choices

Choice (4)Response

a.

6.25 N

b.

6.52 N

c.

2.56 N

d.

65.62 N

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