Laws of Motion-Force and Inertia (NEET Physics): Questions 49 - 54 of 56

Get 1 year subscription: Access detailed explanations (illustrated with images and videos) to 2098 questions. Access all new questions we will add tracking exam-pattern and syllabus changes. View Sample Explanation or View Features.

Rs. 550.00 or

Passage

Read the passage given below and answer the questions that follows:

Finding elongation of the spring

Finding Elongation of the Spring

A bead of mass m is attached to one end of a spring of natural length R

A bead of mass m is attached to one end of a spring of natural length R and spring constant K=(3+1)mgR The other end of the spring is fixed at point A on a smooth ring of radius R as shown in figure. When bead is released to move then

Question number: 49 (1 of 3 Based on Passage) Show Passage

» Laws of Motion » Force and Inertia

MCQ▾

Question

The normal reaction force at B is -

Choices

Choice (4) Response

a.

3 3 mg/2

b.

3 3 mg

c.

3 mg

d.

mg/2

Question number: 50 (2 of 3 Based on Passage) Show Passage

» Laws of Motion » Force and Inertia

MCQ▾

Question

Initial elongation in the spring is -

Choices

Choice (4) Response

a.

2R

b.

R

c.

2R

d.

3R

Question number: 51 (3 of 3 Based on Passage) Show Passage

» Laws of Motion » Force and Inertia

MCQ▾

Question

Tangential acceleration of bead just after it is released.

Choices

Choice (4) Response

a.

3g4

b.

g2

c.

2g3

d.

g4

Question number: 52

» Laws of Motion » Force and Inertia

MCQ▾

Question

A bob is hanging over a pulley inside a car through a string. The second end of the string is in the hand of a person standing in the car. The car is moving with constant acceleration ‘a’ directed horizontally as shown in figure. Other end of the string is pulled with constant acceleration ‘a’ vertically. The tension in the string is –

A bob is hanging over a pulley inside a car through a string

A Bob Is Hanging Over a Pulley Inside a Car Through a String

Finding the tension in the string

Choices

Choice (4) Response

a.

mg2+a2

b.

mg2+a2+ma

c.

m (g - a)

d.

mg2+a2ma

Question number: 53

» Laws of Motion » Force and Inertia

MCQ▾

Question

In the above question, if at the end of 4 sec, the string be cut, the position of each particle in next 2 seconds will respectively be -

Choices

Choice (4) Response

a.

17.856 m, 21.344 m

b.

-17.856 m, -21.344 m

c.

-21.344 m, 17.856 m

d.

-17.856 m, 21.344 m

Question number: 54

» Laws of Motion » Force and Inertia

MCQ▾

Question

The pulley arrangements of fig (A) and (B) are identical. TW mass of the rope is negligible. In (A) the mass m is lifted up by attaching a mass 2 m to the other end of the rope. In (B) I m is lifted up by pulling the other end of the rope with a constant downward force F = 2 mg. Which of the following is correct?

Pulley arrangement with mass and the force

Pulley Arrangement With Mass and the Force

Pulley arrangement with rope

Choices

Choice (4) Response

a.

Acceleration in case B is 3 times more than that in case A

b.

In both the cases, acceleration is same

c.

In case A acceleration is g, while in case B it is 2g

d.

All of the above

Sign In