Kinematics-Uniformly Accelerated Motion (NEET (NTA)-National Eligibility cum Entrance Test (Medical) Physics): Questions 1 - 5 of 23

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Question number: 1

» Kinematics » Uniformly Accelerated Motion

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MCQ▾

Question

The shaft of an electric motor starts from rest and on the application of a torque, it gains an angular acceleration given by a = 3t –t 3 during the first 2 seconds after it starts after which a = 0. The angular velocity after 6 sec will be –

Choices

Choice (4) Response

a.

2 rad/sec

b.

1 rad/sec

c.

4 rad/sec

d.

3 rad/sec

Question number: 2

» Kinematics » Uniformly Accelerated Motion

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MCQ▾

Question

The shaft of an electric motor starts from rest and on the application of a torque, it gains an angular acceleration given by a = 3t –t 2 during the first 2 seconds after it starts after which a = 0. The angular velocity after 6 sec will be –

Choices

Choice (4) Response

a.

30/4 rad/sec

b.

4/30 rad/sec

c.

3/10 rad/sec

d.

10/3 rad/sec

Question number: 3

» Kinematics » Uniformly Accelerated Motion

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MCQ▾

Question

Using rectangular co-ordinates and the unit vectors i and j, the vector expression for the acceleration a will be (r is a position vector) -

Choices

Choice (4) Response

a.

b.

- 2 r

c.

-2r 2

d.

r 2

Question number: 4

» Kinematics » Uniformly Accelerated Motion

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MCQ▾

Question

The angular velocity of a particle is given by co = 1.51 - 3t 2 + 2, the time when its angular acceleration decreases to be zero will be -

Choices

Choice (4) Response

a.

25 sec

b.

1.2 sec

c.

0.25 sec

d.

12 sec

Question number: 5

» Kinematics » Uniformly Accelerated Motion

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Assertion-Reason▾

Question

Assertion (Ꭺ)

In non-uniform circular motion, velocity vector and acceleration vector are not perpendicular to each other.

Reason (Ꭱ)

In non-uniform circular motion, particle has normal as well as tangential acceleration.

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ

b.

Ꭺ is true but Ꭱ is false

c.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

d.

Both Ꭺ and Ꭱ are false

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