Kinematics (NEET Physics): Questions 131  135 of 229
Get 1 year subscription: Access detailed explanations (illustrated with images and videos) to 2098 questions. Access all new questions we will add tracking exampattern and syllabus changes. View Sample Explanation or View Features.
Rs. 550.00 or
Question number: 131
» Kinematics » Average Speed and Instantaneous Velocity
Question
A particle moves in a circle of radius 10cm with a linear speed of 20m/s. The angular velocity will be –
Choices
Choice (4)  Response  

a.  25 rad/s 

b.  75 rad/s 

c.  50 rad/s 

d.  200 rad/s 

Question number: 132
» Kinematics » Motion in a Straight Line
Question
If t _{1} be the time taken by a body to clear the top of a building and be the time spent in air, then t _{2}: t _{1} will be 
Choices
Choice (4)  Response  

a.  2: 1 

b.  1: 1 

c.  1: 2 

d.  1: 4 

Question number: 133
» Kinematics » Motion in a Straight Line
Assertion (Ꭺ)
A cyclist is cycling on rough horizontal circular track with increasing speed. Then the frictional force on cycle is always directed towards center of the circular track.
Reason (Ꭱ)
For a particle moving in a circle, radial component of net force should be directed towards center. You have to select the correct choice.
Choices
Choice (4)  Response  

a.  Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ 

b.  Ꭺ is true but Ꭱ is false 

c.  Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ 

d.  Both Ꭺ and Ꭱ are false 

Question number: 134
» Kinematics » Average Speed and Instantaneous Velocity
Question
The angular speed with which the earth would have to rotate on its axis so that a person on the equator would weigh (3/5) ^{th} as much as present, will be: (Take the equatorial radius as 6400 km)
Choices
Choice (4)  Response  

a.  7.8 x 10 ^{3} rad/sec 

b.  7.8 x 10 ^{4} rad/sec 

c.  8.7 x 10 ^{3} rad/sec 

d.  8.7 x 10 ^{4} rad/sec 

Passage
Velocity at a general point P (x, y) for a horizontal projectile motion is given by
V = =
α is angle made by v with horizontal in clockwise direction Trajectory equation for a horizontal projectile motion is given by x = v _{x} t = ut
y = ( ) gt ^{2 }
Eliminating t, We get y =
Question number: 135 (1 of 3 Based on Passage) Show Passage
» Kinematics » Average Speed and Instantaneous Velocity
Question
An aeroplane is flying horizontally with a velocity of 720 km/h at an altitude of 490 m. When it is just vertically above the target a bomb is dropped from it. How far horizontally it missed the target?
Choices
Choice (4)  Response  

a.  2000 m 

b.  200 m 

c.  1000 m 

d.  100 m 
