# Kinematics (NEET (NTA-National Eligibility cum Medical Entrance Test) Physics): Questions 69 - 73 of 233

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## Question number: 69

» Kinematics » Motion in a Plane

MCQ▾

### Question

A force (where K is a positive constant) acts on a particle moving in the x-y plane. Starting from the origin, the particle is taken along the positive x-axis to the point (a, 0) and then parallel to the y-axis to the point

(a, a). The total work done by the forces F on the particle is

### Choices

Choice (4) Response

a.

2Ka 2

b.

Ka 2

c.

-Ka 2

d.

-2Ka 2

## Question number: 70

» Kinematics » Velocity-Time Graphs

MCQ▾

### Question

A man crosses a 320 m wide river perpendicular to the current in 4 minutes. If in still water he can swim with a speed 5/3 times that of the current, then the speed of the Current in m/min is

### Choices

Choice (4) Response

a.

40

b.

30

c.

50

d.

60

## Question number: 71

» Kinematics » Average Speed and Instantaneous Velocity

MCQ▾

### Question

The length of second’s hand in watch is 1 cm. The change in velocity of its tip in 15 seconds is

### Choices

Choice (4) Response

a.

zero

b.

cm/sec

c.

cm/sec

d.

cm/sec

## Question number: 72

» Kinematics » Average Speed and Instantaneous Velocity

MCQ▾

### Question

A person aiming to reach the exactly opposite point on the bank of a stream is swimming with a speed of 0.5 m/s at an angle of 120° with the direction of flow of water. The speed of water in the stream is

### Choices

Choice (4) Response

a.

lm/s

b.

0.433 m/s

c.

0.25 m/s

d.

0.5 m/s

## Question number: 73

» Kinematics » Motion in a Straight Line

MCQ▾

### Question

A man can swim with velocity v relative to water. He has to cross a river of width d flowing with a velocity u (w > v). The distance through which he is carried downstream by the river is x. Which of the following statements is correct?

### Choices

Choice (4) Response

a.

If he crosses the river in minimum time x = du/v

b.

x cannot be less than du/v

c.

Force to be minimum he has to swim in a direction making an angle

of π/2- sin -1 (v/u) with the direction of the flow of water.

d.

x will be maximum if he swims in a direction making

an angle of π/2 + sin-1 - 1 (v/u) with direction of the flow of water.

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