Electrostatics-Coulomb's Law (NEET (National Eligibility cum Medical Entrance Test) Physics): Questions 5 - 9 of 9

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Question number: 5

» Electrostatics » Coulomb's Law

MCQ▾

Question

In the rectangle shown below, the two corners have charges q 1 = -5 μC and q 2 = +2.0 μC. Find the force acting on the q 2 due to q 1.

Rectangular image given having charge values

Rectangular Image Given Having Charge Values

In figure the rectangular having two charges at corners q1=-5 μC and q2 =+2.0 μC.

Choices

Choice (4) Response

a.

-60N

b.

-30N

c.

-20N

d.

-40N

Passage

A sphere of radius R contains charge density ρ (r) = A (R-r), for 0 The total electric charge inside the sphere is Q.

Question number: 6 (1 of 2 Based on Passage) Show Passage

» Electrostatics » Coulomb's Law

MCQ▾

Question

If charge q is placed at r (r > R) than it would experience force is,

Choices

Choice (4) Response

a.

k q Q r

b.

Equation

c.

Equation

d.

Equation

Question number: 7 (2 of 2 Based on Passage) Show Passage

» Electrostatics » Coulomb's Law

MCQ▾

Question

The electric field outside the sphere is Equation

Choices

Choice (4) Response

a.

Equation

b.

Equation

c.

Equation

d.

Equation

Question number: 8

» Electrostatics » Coulomb's Law

MCQ▾

Question

Electric charges of 1μC, -1μC and 2μC are placed in air at the corners A, B and C respectively of an equilateral triangle ABC having length of each side 10 cm. The resultant force on the charge at C is

Choices

Choice (4) Response

a.

3.6 N

b.

2.7 N

c.

1.8 N

d.

0.9 N

Question number: 9

» Electrostatics » Coulomb's Law

MCQ▾

Question

The charges on two spheres are + 7 μ C and -5 μ C respectively. They experience a force F. If each of them is given an additional charge of -2 μ C, the new force of attraction will be

Choices

Choice (4) Response

a.

F

b.

Equation

c.

Equation

d.

2F

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