Communication System-Need for Modulation (NEET Physics): Questions 1 - 3 of 6

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Question number: 1

» Communication System » Need for Modulation

MCQ▾

Question

The acceleration due to gravity at a place can be determined with the help of a simple pendulum. For this purpose effective length of the pendulum is considered. If ′ be the length of the string and ‘d’ the diameter of the bob then the effective length is equal to

Choices

Choice (4) Response

a.

l + d

b.

l+d2

c.

l-d

d.

ld2

Question number: 2

» Communication System » Need for Modulation

MCQ▾

Question

Students I, II and III perform an experiment for measuring the acceleration due to gravity (g) using a simple pendulum. They use different lengths of the pendulum and/or record time for different number of oscillations. The observations are shown in the table. Least count for length = 0.1 cm

Least count for time = 0.1 s

Table on length of pendulum and number of oscillations

Student

Length of the pendulum (cm)

No. of oscillations

(n)

Total time for (n) oscillations

(s)

Time

Period (s)

I

64.0

8

128.0

16.0

II

64.0

4

64.0

16.0

III

20.0

4

36.0

9.0

If E I, E II and E III are the percentage errors in g, i. e. , ( Δgg×100) for students, I, II and III, respectively, then

Choices

Choice (4) Response

a.

E I = 0

b.

E I = E II

c.

E I is minimum

d.

E II is maximum

Question number: 3

» Communication System » Need for Modulation

MCQ▾

Question

An oscillator is producing FM waves of frequency 4 kHz and modulating index is 8. Thus calculate the variation.

Choices

Choice (4) Response

a.

5.0

b.

0.20

c.

0.67

d.

1.5

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