NEET (NTA)-National Eligibility cum Entrance Test (Medical) Physics: Questions 1802 - 1806 of 2184

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Question number: 1802

» Gravitation » Gravitational Acceleration

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MCQ▾

Question

Two planets of radii in the ratio 2: 3 are made from the materials of density in the ratio 3: 2. Then the ratio of acceleration due to gravity at the surface of two planets will be,

Choices

Choice (4) Response

a.

2.25

b.

c.

0.12

d.

1

Question number: 1803

» Experimental Skills » Potentiometer

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Question

Two potentiometers A and B having 4 wires and 10 wires, each having 100 cm in length are used to compare e. m. f. of 2 cells. Which one will give a larger balancing length?

Choices

Choice (4) Response

a.

Potentiometer A

b.

Potentiometer B

c.

Balancing length doesn’t depend on the total length of the wire.

d.

A and B will give same balancing length

Question number: 1804

» Communication System » Basic Elements of Communication System

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Question

If μ 1 and μ 2 are two refractive indices of the materials of core and cladding of an optical fiber, then the loss of light due to its leakage can be minimized by having

Choices

Choice (4) Response

a.

μ 1 > μ 2

b.

μ 1 = μ 2

c.

μ 1 < μ 2

d.

Question does not provide sufficient data or is vague

Question number: 1805

» Gravitation » Energy

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Question

A body of mass 100 kg falls on the earth from infinity. What will be its energy on reaching the earth? Radius of the earth is 6400 km and g = 9.8 m/s 2. Air friction is negligible.

Choices

Choice (4) Response

a.

6.27 ⨯ 10 9 J

b.

6.27 ⨯ 10 8 J

c.

6.27 ⨯ 10 10 J

d.

6.27 ⨯ 10 7 J

Passage

Read the passage given below and answer the questions that follow:

Consider a block of conducting material of resistivity ′ ρ ′ shown in the figure. Current I enter at ‘A’ and leaves from ‘D’. We apply superposition principle to find voltage ∆ V’ developed between ‘B’ and ‘C’. The calculation is done in the following steps:

(i) Take current T entering from ‘A’ and assume it to spread over a hemispherical surface in the block

A block of conducting material

A Block of Conducting Material

In figure a block of conducting material of resistivity ρ shown in figure. Current I enter at A and leaves from D.

(ii) Calculate field E (r) at distance ‘r’ from A by using Ohm’s law E = ρ j, where j is the current per unit area at ‘r’.

(iii) From the V dependence of E (r), obtain the potential V (r) at r.

(iv) Repeat (i), (ii) and (iii) for current

Question number: 1806 (1 of 2 Based on Passage) Show Passage

» Experimental Skills » Resistivity of the Material

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Question

∆V measured between B and C is,

Choices

Choice (4) Response

a.

b.

c.

d.