NEET (NTA)National Eligibility cum Entrance Test (Medical) Physics: Questions 169  173 of 2184
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Question number: 169
» Kinematics » Average Speed and Instantaneous Velocity
Question
A ball is thrown horizontally from a height of 20 m. It hits) the ground with a velocity three times its initial velocity. The initial velocity of ball is
Choices
Choice (4)  Response  

a.  5 m/s 

b.  7 m/s 

c.  2 m/s 

d.  3 m/s 

Question number: 170
» Kinematics » Average Speed and Instantaneous Velocity
Question
A particle is projected with a velocity u so that its horizontal range is twice the maximum height attained. The horizontal range is
Choices
Choice (4)  Response  

a. 


b. 


c. 


d. 


Question number: 171
» Kinematics » Uniformly Accelerated Motion
Question
A grind stone starts from rest and has a constantangular acceleration of 6.0 rad/sec2. The angular displacement and angular velocity, after 4 sec. will respectively be
Choices
Choice (4)  Response  

a.  32 rad, 64 rad/s 

b.  48 rad, 24 rad/s 

c.  64 rad, 32 rad/s 

d.  16 rad, 32 rad/s 

Passage
The velocity of the particle changes moving on the curved path, this change in velocity is brought by a force known as centripetal force and the acceleration so produced in the body is known as centripetal acceleration. The direction of centripetal force or acceleration is always towards the center of circular path.
Question number: 172 (1 of 1 Based on Passage) Show Passage
» Kinematics » Average Speed and Instantaneous Velocity
Question
A ball is fixed to the end of a string and is rotated in a horizontal circle of radius 5 m with a speed of 10 m/sec. The acceleration of the ball will be 
Choices
Choice (4)  Response  

a.  20 m/s ^{2} 

b.  30 m/s ^{2} 

c.  40 m/s ^{2} 

d.  10 m/s ^{2} 

Question number: 173
» Kinematics » Average Speed and Instantaneous Velocity
Question
A particle describes a horizontal circle on the smooth surface of an inverted cone. The height of the plane of the circle above the vertex is 9.8 cm, then choose the correct options
(1) The speed of the particle will be 0.98 m/s
(2) tan 0 = rg/v ^{2} (6 is semiapex angle)
(3) The speed of the particle will be 98 m/s
(4) tan 9 = rg/v (0 is semi apex angle)
Choices
Choice (4)  Response  

a.  1,2 and 3 

b.  1 and 3 

c.  2 and 4 

d.  1 and 2 
