NEET (NTA)-National Eligibility cum Entrance Test (Medical) Physics: Questions 863 - 865 of 2184

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Question number: 863

» Work, Energy and Power » Work Done

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MCQ▾

Question

A uniform rod of length 4 m and mass 20 kg is lying horizontal on the ground. The work done in keeping it vertical with one of its ends touching the ground, will be –

Choices

Choice (4) Response

a.

784 J

b.

98 J

c.

392 J

d.

196 J

Question number: 864

» Laws of Motion » Laws of Friction

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Assertion-Reason▾

Question

Assertion (Ꭺ)

A solid sphere and a hollow sphere of same mass M and same radius R are released from the top of a rough inclined plane. Friction coefficient is same for both the bodies. If both bodies perform imperfect rolling, then Work done by friction for the motion of bodies from top of incline to the bottom will be same for both the sides.

Reason (Ꭱ)

Force of friction will be same for both the bodies.

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are false

b.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

c.

Ꭺ is true but Ꭱ is false

d.

Ꭺ is false but Ꭱ is true

Question number: 865

» Laws of Motion » Laws of Friction

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Assertion-Reason▾

Question

Assertion (Ꭺ)

Maximum value of friction force between two surfaces is u x normal reaction. Where u = coefficient of friction between surfaces.

Reason (Ꭱ)

Friction force between surfaces of two bodies is always less than or equal to externally applied force.

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

b.

Both Ꭺ and Ꭱ are false

c.

Ꭺ is false but Ꭱ is true

d.

Ꭺ is true but Ꭱ is false