NEET (NTA)-National Eligibility cum Entrance Test (Medical) Physics: Questions 53 - 57 of 2184

Access detailed explanations (illustrated with images and videos) to 2184 questions. Access all new questions we will add tracking exam-pattern and syllabus changes. Subscription can be renewed yearly absolutely FREE! View Sample Explanation or View Features.

Rs. 550.00 or

How to register?

Question number: 53

» Dual Nature of Matter and Radiation » Hertz and Lenard's Observations

Edit
Assertion-Reason▾

Question

Assertion (Ꭺ)

Unit of Rydberg constant R is m-l

Reason (Ꭱ)

It follows from Bohr’s formula v = R [

-

] the symbols have their usual meaning.

Choices

Choice (4) Response

a.

Ꭺ is false but Ꭱ is true

b.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

c.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ

d.

Both Ꭺ and Ꭱ are false

Question number: 54

» Kinematics » Motion in a Straight Line

Edit
MCQ▾

Question

A body travels for 15 second starting from rest with constant acceleration. If it travels distances S 1, S 2 and S 3, in the first five seconds, second five seconds and next five seconds respectively the relation between S 1, S 2 and S 3 is

Choices

Choice (4) Response

a.

s 1 = s 2 = s 3

b.

s 1 =

s 2 =

s 3

c.

5s 1 = 3s 2 = s 3

d.

s 1 =

s 2 =

s 3

Question number: 55

» Physics and Measurement » Accuracy and Precision of Measuring Instruments

Edit
MCQ▾

Question

A wire has a mass 0.3 + 0.003g, radius 0.5 + 0.005 mm and length 6 + 0.06 cm. The maximum percentage error in the measurement of its density is

Choices

Choice (4) Response

a.

2

b.

3

c.

1

d.

4

Question number: 56

» Physics and Measurement » SI Units

Edit
MCQ▾

Question

What is the relationship between dyne and newton of force?

Choices

Choice (4) Response

a.

l dyne = 107 newton

b.

1 dyne = 10-7 newton

c.

1 dyne = 10 - 5 newton

d.

l dyne = 105 newton

Question number: 57

» Kinematics » Motion in a Straight Line

Edit
MCQ▾

Question

A particle moves along x-axis with acceleration a = a 0 (1 –t/T) where a 0 and T are constants if velocity at t = 0 is zero then find the average velocity from t = 0 to the time when a = 0.

Choices

Choice (4) Response

a.

b.

c.

d.