NEET (NTA)-National Eligibility cum Entrance Test (Medical) Chemistry: Questions 1 of 1224

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» Chemical Thermodynamics » First Law of Thermodynamics » Work

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Question

When 50 g of iron is dissolved in HCl at 25°C in an open vessel and atmospheric pressure is 1 atm, calculate the work done?

Choices

Choice (4) Response

a.

-22.123 J

b.

-2212.39 J

c.

-21.84 J

d.

22.123 J

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Topic %Score

%Score

Ques. Time s

Answer

c.

Explanation

When iron is dissolves in HCl, hydrogen is produced

Fe + 2HCl → FeCl 2 + H 2

From the ideal gas equation PV = nRT

From the given data

n = weight/molecular weight

=50/56

By substituting the values in above equation

This is equal to volume change when reaction is carried out in open beaker.

Work done by the system W=-P∆V

=-1.0

=-2212.39J.

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