Hydrocarbons-Alkynes (NEET (NTA)-National Eligibility cum Entrance Test (Medical) Chemistry): Questions 1 - 5 of 28

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Question number: 1

» Hydrocarbons » Alkynes » Addition of Hydrogen, Halogens, Water and Hydrogen Halides

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MCQ▾

Question

What will be the product of chlorine water and acetylene?

Choices

Choice (4) Response

a.

Dichloro propanol

b.

2-Chloroethanol

c.

Propanol

d.

Dichloro ethanal

Question number: 2

» Hydrocarbons » Alkynes » Addition of Hydrogen, Halogens, Water and Hydrogen Halides

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MCQ▾

Question

The triply bonded carbon atoms

(1) Are sp hybridised

(2) Are sp3 hybridised

(3) Have two pi bonds and one sigma bonds

(4) Have three sigma bonds and one pi bond

In the following questions, more than one of the answers given are correct. Select the correct answers and mark it according to the following codes:

Choices

Choice (4) Response

a.

2 and 4 are correct

b.

1,2 and 3 are correct

c.

1 and 2 are correct

d.

1 and 3 are correct

Question number: 3

» Hydrocarbons » Alkynes » Addition of Hydrogen, Halogens, Water and Hydrogen Halides

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MCQ▾

Question

Acetylene magnesium chloride reacts with ethyl bromide, what will be the product?

Choices

Choice (4) Response

a.

1-butene

b.

1,3-butadiene

c.

2-butyne

d.

1.2-butadicnc

Question number: 4

» Hydrocarbons » Alkynes » Addition of Hydrogen, Halogens, Water and Hydrogen Halides

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MCQ▾

Question

The alcohol which easily reacts with cone. HC1 is

Choices

Choice (4) Response

a.

(CH3) 3-C-OH

b.

(CH3) 3 -C - CH2 OH

c.

CH3-CH2-CH2-CH2-OH

d.

CH3-CHOH-CH2-CH3

Question number: 5

» Hydrocarbons » Alkynes » Acidic Character

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Assertion-Reason▾

Question

Assertion (Ꭺ)

The reaction rates of alkynes with electrophiles are slower than those of alkenes.

Reason (Ꭱ)

The steric and electronic factors play the part in diminishing the reactivity of alkynes toward electrophiles.

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ

b.

Both Ꭺ and Ꭱ are false

c.

Ꭺ is true but Ꭱ is false

d.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

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