Basic Concepts in Chemistry-Empirical and Molecular Formulae (NEET Chemistry): Questions 7 - 10 of 10

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Passage

Read the passage given below and answer the questions that follows :

The oxidation state of the elements in the pure state = 0. The equivalent wt. of the element

E = Atomicwtoftheelementx where x = valency

The equivalent wt. of any compound = sum of the equivalent wt. of component elements or ions.

By using this relation we can calculate the equivalent wt. of any acidic and basic oxide.

Question number: 7 (1 of 2 Based on Passage) Show Passage

» Basic Concepts in Chemistry » Empirical and Molecular Formulae

MCQ▾

Question

Equiv. wt. of As2O3 is -

Choices

Choice (4) Response

a.

33

b.

46.34

c.

26.5

d.

38.3

Question number: 8 (2 of 2 Based on Passage) Show Passage

» Basic Concepts in Chemistry » Empirical and Molecular Formulae

MCQ▾

Question

Equiv. wt. of Fe2O3 is -

Choices

Choice (4) Response

a.

33

b.

26.5

c.

38.3

d.

46.34

Question number: 9

» Basic Concepts in Chemistry » Empirical and Molecular Formulae

MCQ▾

Question

In acting as a reducing agent, a piece of metal M weighing 16 grams gives up 2.25×1023 electrons. What is the equivalent weight of the metal?

Choices

Choice (4) Response

a.

42.83

b.

32

c.

83.32

d.

21.33

Question number: 10

» Basic Concepts in Chemistry » Empirical and Molecular Formulae

MCQ▾

Question

Two elements X and Y have atomic mass 75 and 16 respectively. They combine to give a compound having 75.8% X. The formula of the compound is?

Choices

Choice (4) Response

a.

X2Y3

b.

XY

c.

X2Y2

d.

X2Y

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