NEET Chemistry: Questions 264 - 271 of 891

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Question number: 264

» P-Block Elements Group 13 to 18 » Group 17 » Oxides and Oxoacids of Halogens

MCQ▾

Question

The oxidation number of chlorine in the final product B in the following sequence of reaction is; KClO4+H2SO4KHSO4+AB

Choices

Choice (4) Response

a.

-1

b.

+3

c.

+7

d.

+5

Question number: 265

» Atomic Structure » Spin Quantum Number

MCQ▾

Question

If the set of quantum number of an element is n = 4, l = 0, m = 0 and s=+1/2. Identify that element.

Choices

Choice (4) Response

a.

Scandium

b.

Sodium

c.

Potassium

d.

Titanium

Question number: 266

» P-Block Elements Group 13 to 18 » Group 18 » Structures of Fluorides

MCQ▾

Question

Which of following is planar in shape?

Choices

Choice (4) Response

a.

XeF4

b.

XeO4

c.

XeOF4

d.

XeO2F2

Question number: 267

» Atomic Structure » Spin Quantum Number

MCQ▾

Question

Correct set of four quantum numbers for the outermost electron of rubidium (Z = 37) is -

Choices

Choice (4) Response

a.

6, 0, 0, ½

b.

5, 0, 0, 1/2

c.

5, 1, 0, 1/2

d.

5, 1, 1, 1/2

Question number: 268

» P-Block Elements Group 13 to 18 » Group 18 » Noble Gases

MCQ▾

Question

The element having highest ionization potential is?

Choices

Choice (4) Response

a.

Hydrogen

b.

Helium

c.

Nitrogen

d.

Oxygen

Question number: 269

» Atomic Structure » Spin Quantum Number

MCQ▾

Question

The maximum number of atomic orbitals associated with a principal quantum number 3 is

Choices

Choice (4) Response

a.

9

b.

16

c.

12

d.

25

Question number: 270

» Basic Concepts in Chemistry » Empirical and Molecular Formulae

MCQ▾

Question

In acting as a reducing agent, a piece of metal M weighing 20 grams gives up 3.30×1023 electrons. What is the equivalent weight of the metal?

Choices

Choice (4) Response

a.

36.50

b.

83.32

c.

32

d.

42.83

Question number: 271

» P-Block Elements Group 13 to 18 » Group 17 » Hydrogen Halides

MCQ▾

Question

HBr and HI cannot be prepared by heating bromides and iodides with concentrated H2SO4 because?

Choices

Choice (4) Response

a.

HBr and HI are weak oxidizing agent

b.

HBr and HI are strong reducing agents

c.

HBr and HI are weak reducing agent

d.

HBr and HI are strong oxidizing agents

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