Sequence and Series (KVPY (Kishore Vaigyanik Protsahan Yojana) Stream SBSX (Class 12 & 1st Year B.Sc.) Math): Questions 1  6 of 9
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Question number: 1
» Sequence and Series » Geometric Progressions
Appeared in Year: 2011
Question
Suppose n is a natural number such that where is the square root of – 1. Then n is –
Choices
Choice (4)  Response  

a.  18 

b.  9 

c.  36 

d.  72 

Question number: 2
» Sequence and Series » Arithmetico  Geometric Progression
Appeared in Year: 2011
Question
The minimum value of n for which
Choices
Choice (4)  Response  

a.  Is 101 

b.  Is 121 

c.  Is 151 

d.  All of the above 

Question number: 3
» Sequence and Series » Geometric Progressions
Appeared in Year: 2010
Question
The number of natural numbers n in the interval [500, 2010] for which the polynomial divides the polynomial is –
Choices
Choice (4)  Response  

a.  1006 

b.  503 

c.  100 

d.  0 

Question number: 4
» Sequence and Series » Geometric Progressions
Appeared in Year: 2010
Question
Suppose the sides of a triangle form a geometric progression with common ratio r. Then r lies in the interval –
Choices
Choice (4)  Response  

a. 


b. 


c. 


d. 


Question number: 5
» Sequence and Series » Arithmetic Series
Appeared in Year: 2012
Question
Define a sequence by for . Then
Choices
Choice (4)  Response  

a.  Equals 

b.  Equals 

c.  Equals 1 

d.  None of the above 

Question number: 6
» Sequence and Series » N Terms of Special Series (Squares & Cubes)
Appeared in Year: 2014
Question
Let be an integer. For a permutation of we let . Let be the sum of the roots of and let denote the sum over all permutation of of the number . Then
Choices
Choice (4)  Response  

a. 


b. 


c. 


d. 

