Laws of Motion-Equilibrium of Concurrent Forces (KVPY Stream-SA (Class 11) Physics): Questions 1 - 2 of 4

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Question number: 1

» Laws of Motion » Equilibrium of Concurrent Forces

Appeared in Year: 2011

MCQ▾

Question

A small child tries to moves a large rubber toy placed on the ground. The toy does not move but gets deformed under her pushing force (F) which is obliquely upward as shown. Then,

A large rubber toy is pushed by a child

A Large Rubber Toy Is Pushed by a Child

Figure shows a small child tries to moves a large rubber toy placed on the ground.

Choices

Choice (4) Response
a.

The normal force by the ground is equal and opposite to the weight of the toy

b.

The resultant of the pushing force (F) , weight of the toy, normal force by the ground on the toy and the frictional force is zero.

c.

The pushing force (F) of the child is balanced by the equal and opposite frictional force

d.

The pushing force (F) of the child is balanced by the total internal force in the toy generated due to deformation.

Question number: 2

» Laws of Motion » Equilibrium of Concurrent Forces

Appeared in Year: 2011

MCQ▾

Question

An object with uniform density ρ is attached to a spring that is known to stretch linearly with applied force as shown below.

 A object attached to a spring and immersed in liquid

a Object Attached to a Spring and Immersed in Liquid

Figure shows an object attached to a spring that is known to stretch linearly with applied force as shown below and this object-spring system is immersed in a liquid of density ρ1.

When the spring-object system is immersed in a liquid of density ρ 1 as shown in the figure, the spring stretches by an amount x 1 (ρ > ρ 1). When the experiment is repeated in a liquid of density (ρ 2 < ρ 1), the spring stretches by an amount x 2. Neglecting any buoyant force on the spring, the density of the object is

Choices

Choice (4) Response
a.

ρ=ρ1X1+ρ2X2X1+X2

b.

ρ=ρ1X2ρ2X1X2X1

c.

ρ=ρ1X2+ρ2X1X1+X2

d.

ρ=ρ1X1ρ2X2X1X2

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