# KVPY (Kishore Vaigyanik Protsahan Yojana) Stream-SA (Class 11) Math: Questions 1 of 265

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MCQ▾

### Question

Two friends P and Q are 50 km apart and they start simultaneously on cycles to meet each other. The speed of P is 4 times than that of Q. The distance between them decreases at the rate of 2 km per minute. Fifteen minutes after they start, P’s cycle breaks down and P stops and waits for Q to arrive. After how much time (in minutes) P started riding, does Q meet P?

### Choices

Choice (4) Response

a.

55

b.

70

c.

60

d.

65

## Analysis

### Timing

Ques. Time s

Session Time s

Avg. Per Ques. (Topic)0 s

Avg. Per Ques. (Overall)0 s

d.

## Explanation

Here from given data speed of P is 4 times that of Q, Therefore if;

Speed of Q = V km/hr

Speed of P = 4V km/hr

The distance between P and Q decreases at the rate of 2 km per minute.

Now, Distance covered by then after 15 min is,

So, remaining distance = (50 – 30) = 20 km

Time taken by Q to cover 20 km is,

Therefore total time is,