Atomic StructureDeBroglie's Relationship (KVPY StreamSA (Class 11) Chemistry): Questions 1  5 of 5
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Question number: 1
» Atomic Structure » DeBroglie's Relationship
Question
Iodine molecule dissociates after absorbing light of 4500Å. If each molecule absorbs one quantum radiation, calculate the kinetic energy of iodine atom. (Bond energy of ).
Choices
Choice (4)  Response  

a. 


b. 


c. 


d. 


Question number: 2
» Atomic Structure » DeBroglie's Relationship
Question
If the energy difference between the ground state of an atom and its excited state is , what is the wavelength of the photon required producing this transition.
Choices
Choice (4)  Response  

a.  4.517×10  7m 

b. 


c. 


d.  4.517×107m 

Question number: 3
» Atomic Structure » DeBroglie's Relationship
Appeared in Year: 2014
Question
If the Planck’s constant h = Js, the deBroglie wavelength of a particle having momentum of kg. m. s^{1} will be 
Choices
Choice (4)  Response  

a.  0.2 Å 

b.  0.02 Å 

c.  0.002 Å 

d.  2 Å 

Passage
Einstein had suggested that light could behave as a wave as well as like a particle i. e. it has dual character. In 1924, deBroglie proposed that an electron, behaves both as a material particle and as a wave. This proposed a new theory wave mechanical theory of matter. According to this theory, the electrons, protons and even atom when in motion possess wave properties. According to deBroglie, the wavelength associated with a particle of mass m, moving with velocity v is given by the relation, λ = h/mv where h is Planck’s constant.
Question number: 4 (1 of 2 Based on Passage) Show Passage
» Atomic Structure » DeBroglie's Relationship
Question
For particles having same kinetic energy, the de Broglie wavelength is 
Choices
Choice (4)  Response  

a.  Inversely proportional to its velocity 

b.  Independent of velocity and mass 

c.  Directly proportional to its velocity 

d.  unpredictable 

Question number: 5 (2 of 2 Based on Passage) Show Passage
» Atomic Structure » DeBroglie's Relationship
Question
Velocity of helium atom at 300K is 2.40 x 10^{2} meter per sec. What is its wavelength, (mass number of helium is 4)?
Choices
Choice (4)  Response  

a.  8000 Å 

b.  0.83 nm 

c.  803 Å 

d.  0.416 nm 
