Atomic Structure (KVPY Stream-SA (Class 11) Chemistry): Questions 26 - 30 of 30

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Question number: 26

» Atomic Structure » Shapes of S, P and D - Orbitals

MCQ▾

Question

Choose the correct statements -

(1) Designation for the orbital with the quantum number n = 3, ℓ = 1, m =-1 may be 3px or 3py

(2) Designation for the orbital with the quantum number n = 4, = 2, m =+2 may be 4dxy or 4d x2 – y2

(3) Designation for me orbital with the quantum number n = 5, = 0, m = 0 may be 5s

(4) Designation for the orbital with the quantum number n = 2, = 1, m = 0 may be 3pz

Choices

Choice (4) Response

a.

1, 2 and 3 are correct

b.

1 and 2 are correct

c.

1 and 3 are correct

d.

2 and 4 are correct

Passage

Einstein had suggested that light could behave as a wave as well as like a particle i. e. it has dual character. In 1924, de-Broglie proposed that an electron, behaves both as a material particle and as a wave. This proposed a new theory wave mechanical theory of matter. According to this theory, the electrons, protons and even atom when in motion possess wave properties. According to de-Broglie, the wavelength associated with a particle of mass m, moving with velocity v is given by the relation, λ = h/mv where h is Planck’s constant.

Question number: 27 (1 of 3 Based on Passage) Show Passage

» Atomic Structure » De-Broglie's Relationship

MCQ▾

Question

Velocity of helium atom at 300K is 2.40 x 102 meter per sec. What is its wavelength, (mass number of helium is 4)?

Choices

Choice (4) Response

a.

8000 Å

b.

0.83 nm

c.

803 Å

d.

0.416 nm

Question number: 28 (2 of 3 Based on Passage) Show Passage

» Atomic Structure » De-Broglie's Relationship

MCQ▾

Question

For particles having same kinetic energy, the de Broglie wavelength is -

Choices

Choice (4) Response

a.

Inversely proportional to its velocity

b.

Independent of velocity and mass

c.

Directly proportional to its velocity

d.

unpredictable

Question number: 29 (3 of 3 Based on Passage) Show Passage

» Atomic Structure » Quantum Mechanics

MCQ▾

Question

K. E. Of the electron is 4.55×1025J . Calculate the frequency of its wave.

Choices

Choice (4) Response

a.

7.39×109sec1

b.

1.87×103sec1

c.

1.37×109sec1

d.

5.37×1019sec1

Question number: 30

» Atomic Structure » Heisenberg Uncertainty Principle

MCQ▾

Question

Calculate the uncertainty in the position of an electron if the uncertainty in its velocity is 5.7×105m/s

Choices

Choice (4) Response

a.

1.012×1010m

b.

2.76×1018m

c.

5.77×1016m

d.

0.162×1018m

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