JEE (Based on NTA Guidelines-IIT Engg.) Mains Chemistry: Questions 1 of 2980

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Question MCQ▾

When 50 g of iron is dissolved in HCl at 25°C in an open vessel and atmospheric pressure is 1 atm, calculate the work done?

Choices

Choice (4)Response

a.

-22.123 J

b.

-21.84 J

c.

22.123 J

d.

-2212.39 J

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Answer

b.

Explanation

When iron is dissolves in HCl, hydrogen is produced

Fe + 2HCl ⇾ FeCl2 + H2

From the ideal gas equation PV = nRT

From the given data

n = weight/molecular weight

=

By substituting the values in above equation

This is equal to volume change when reaction is carried out in open beaker.

Work done by the system W =-P ∆ V

=-1.0

=-2212.39J.