ISS (Statistical Services) Statistics Paper II (Old Subjective Pattern): Questions 19 - 24 of 39

Access detailed explanations (illustrated with images and videos) to 39 questions. Access all new questions- tracking exam pattern and syllabus. View the complete topic-wise distribution of questions. Unlimited Access, Unlimited Time, on Unlimited Devices!

View Sample Explanation or View Features.

Rs. 200.00 -OR-

How to register? Already Subscribed?

Question 19

Appeared in Year: 2014

Describe in Detail

Essay▾

Let X be r. v. with pmf under H0 and H1 given below. Find M. P. test with α = 0.03

Finding a Values of F0 (X) and F1 (X) to Given a Table
x123456
f0 (x)0.010.010.010.010.010.95
f1 (x)0.050.040.030.020.010.85

Explanation

To find the M. P. test, first we compute

Finding a Values of P (Z = Z) and Fz (Z) to Given a Table
Z543210.8947

The possible value of Z is

Finding a Values of P (Z = Z) and Fz (Z) to Given a Table
Z543210.8947
P (Z = z)
FZ (z)1

The next step is to find k > 0 and γ such that

Consider k such that Fz (k-) ⩽ α ⩽ Fz (k)

So, we choose k = 5,

The M. P. test is

… (8 more words) …

Question 20

Maximum Likelihood
Edit

Appeared in Year: 2014

Describe in Detail

Essay▾

Let X be exponentially distributed with parameter θ. Obtain MLE of θ based on a sample of size n, from the above distribution.

Explanation

Let X be exponentially distributed with parameter θ.

The likelihood function is

The log-likelihood function is

Differentiable with respect to θ, equating to zero

… (2 more words) …

Question 21

Confidence Interval Estimation
Edit

Appeared in Year: 2015

Describe in Detail

Essay▾

Let y1 , y2, … , yn be a random sample from N (µ, σ 2) where µ and σ 2 are both unknown. Obtain a confidence interval of µ with confidence coefficient (1-α)

Explanation

When population mean and population standard deviation in not know. If is the samplemean and replace σ by its estimate s and tα/2 be the critical value of the student t-test such that have of the area on the left hand side and other half on the right side that is

For first inequality we get

From second

Combining the inequalities

The confidence interva…

… (4 more words) …

Question 22

Sufficient Estimator

Appeared in Year: 2015

Describe in Detail

Essay▾

Obtain the sufficient statistics for the following distribution.

(i)

(ii)

Explanation

By using factorization theorem, the condition is that

where h (x) is free from θ and g (.) depends on X only through T.

(i)

The joint pdf of random sample is

Let T = . By factorization theorem

h (x) = 1,

So, h (x) is free from θ and g depends on sample only through T = .

Thus, T = is sufficient for this distribution.

(ii)

The joint pdf of random sample …

… (31 more words) …

Question 23

Use for Testing
Edit

Appeared in Year: 2015

Describe in Detail

Essay▾

Show that T 2 statistic is invariant under changes in the unit of measurements for a p×1 random vector X of the form Y = C X + d where C is a p×p nonsingular matrix, d is a p×1 vector.

Explanation

T 2 statistic can be computed from X . Here we have to compute it form Y and both will be same. Here

Let , then and

So, T 2 -statistic comes into existence for testing hypothesis of the form

Since is known vector,

If we have a setup

and

T 2 computed from X is

This is the T 2 statistic which is computed from Y vector.

Question 24

Edit

Appeared in Year: 2015

Describe in Detail

Essay▾

For a sequential probability ratio test of strength (α, β) and stopping bounds are A and B (B < A) , show that A⩽1-β/α and B ⩾ β/1-α

Explanation

Let X = (X1, … , Xk) and also let Ek be the set of all points in k dimensional Euclidean space Rk, for which we reject H0 using the sequential probability ratio test. Also, let Fk be the set of all points in Rk for which we accept H0. Notice that (Ek, k = 1,2, …) are mutually disjoint and (Fk, k = 1,2, …) are also mutually disjoint. Assume that Th&#8230;

… (37 more words) …