Statistical Inference and Hypothesis Testing (ISS Statistics Paper II (New 2016 MCQ Pattern)): Questions 118 - 121 of 222

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Question number: 118

» Statistical Inference and Hypothesis Testing » Confidence Interval Estimation

MCQ▾

Question

The Government conducts national survey to study about the home gardening.

A random sample of 250 households is taken, which have their own vegetable gardens. The average size of their gardens is 643 sq. ft. The calculated standard deviation is σ = 247 sq. ft. Then 90 % confidence interval for the mean size µ, of all household vegetable gardens is

Choices

Choice (4) Response

a.

Equation

b.

Equation

c.

Equation

d.

Equation

Question number: 119

» Statistical Inference and Hypothesis Testing » Confidence Interval Estimation

MCQ▾

Question

Formula for the Confidence interval with Equation confidence coefficient for the variance Equation of the Normal distribution Equation when Equation is known, is given by

Choices

Choice (4) Response

a.

Equation

b.

Equation

c.

Both a. and b. are correct

d.

Question does not provide sufficient data or is vague

Question number: 120

» Statistical Inference and Hypothesis Testing » Moments and Least Squares

MCQ▾

Question

Linear estimators obtained by the method of least squares are

Choices

Choice (4) Response

a.

MVU Estimators

b.

Sufficient Estimators

c.

Unbiased Estimators

d.

Question does not provide sufficient data or is vague

Question number: 121

» Statistical Inference and Hypothesis Testing » Confidence Interval Estimation

MCQ▾

Question

The Government conducts national survey to study about the home gardening.

A random sample of 250 households is taken which have vegetable gardens. The average size of their gardens is 643 square feet. The calculated standard deviation is σ = 247 square feet. How can you interpret the result at 90 % for confidence interval?

Choices

Choice (4) Response

a.

Probability that mean size of household vegetable gardens lies in the interval 617.31 and 668.69 is 0.90

b.

617.31 and 668.69 are 90 percent confidence limits

c.

The length of the confidence interval is 51.38

d.

All a. , b. and c. are correct

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