IMO- Mathematics Olympiad (SOF) Class 7: Questions 588 - 589 of 1012

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Question number: 588

» Triangle and Its Properties

MCQ▾

Question

In a triangle ABC, and D is the mid – point of BC. The value of is equal to ________.

Choices

Choice (4) Response

a.

b.

c.

d.

Question number: 589

» Triangle and Its Properties

MCQ▾

Question

In the figure (not drawn to scale), EFA is a right-angled triangle with and FGB is an equilateral triangle, find .

Triangle poly1 Triangle poly1: Polygon A, B, CQuadrilateral poly2 Quadrilateral poly2: Polygon B, E, F, CArc k Arc k: Semicircle through D and HArc p Arc p: Semicircle through I and JArc q Arc q: Semicircle through K and LSegment c Segment c: Segment [A, B] of Triangle poly1Segment a Segment a: Segment [B, C] of Triangle poly1Segment b Segment b: Segment [C, A] of Triangle poly1Segment b_1 Segment b_1: Segment [B, E] of Quadrilateral poly2Segment d Segment d: Segment [E, F] of Quadrilateral poly2Segment e Segment e: Segment [F, C] of Quadrilateral poly2Segment c_1 Segment c_1: Segment [C, B] of Quadrilateral poly2Segment f Segment f: Segment [B, F] Segment g Segment g: Segment [C, G] Segment h Segment h: Segment [G, F] Point A A = (4.5,4.82) Point A A = (4.5,4.82) Point A A = (4.5,4.82) Point B B = (3.18,3.38) Point B B = (3.18,3.38) Point B B = (3.18,3.38) Point C C = (4.48,3.38) Point C C = (4.48,3.38) Point C C = (4.48,3.38) Point E E = (1.42,1.52) Point E E = (1.42,1.52) Point E E = (1.42,1.52) Point F F = (4.42,1.52) Point F F = (4.42,1.52) Point F F = (4.42,1.52) Point G G = (5.7,3.38) Point G G = (5.7,3.38) Point G G = (5.7,3.38) y text1 = “y”x text1_1 = “x”92â° text1_2 = “92â°”

Image of a Triangle EFA That is Right Angled

Showing an image of a triangle EFA that is right angled, so find y – 2x.

Choices

Choice (4) Response

a.

8

b.

2

c.

17

d.

20

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