IMO Level 1- Mathematics Olympiad (SOF) Class 7: Questions 631 - 631 of 1022

Access detailed explanations (illustrated with images and videos) to 1022 questions. Access all new questions we will add tracking exam-pattern and syllabus changes. Subscription can be renewed yearly absolutely FREE! View Sample Explanation or View Features.

Rs. 450.00 or

How to register?

Question number: 631

» Triangle and Its Properties



In the figure (not drawn to scale), EFA is a right-angled triangle with and FGB is an equilateral triangle, find .

Triangle poly1 Triangle poly1: Polygon A, B, C Quadrilateral poly2 Quadrilateral poly2: Polygon B, E, F, C Arc k Arc k: Semicircle through D and H Arc p Arc p: Semicircle through I and J Arc q Arc q: Semicircle through K and L Segment c Segment c: Segment [A, B] of Triangle poly1 Segment a Segment a: Segment [B, C] of Triangle poly1 Segment b Segment b: Segment [C, A] of Triangle poly1 Segment b_1 Segment b_1: Segment [B, E] of Quadrilateral poly2 Segment d Segment d: Segment [E, F] of Quadrilateral poly2 Segment e Segment e: Segment [F, C] of Quadrilateral poly2 Segment c_1 Segment c_1: Segment [C, B] of Quadrilateral poly2 Segment f Segment f: Segment [B, F] Segment g Segment g: Segment [C, G] Segment h Segment h: Segment [G, F] Point A A = (4.5,4.82) Point A A = (4.5,4.82) Point A A = (4.5,4.82) Point B B = (3.18,3.38) Point B B = (3.18,3.38) Point B B = (3.18,3.38) Point C C = (4.48,3.38) Point C C = (4.48,3.38) Point C C = (4.48,3.38) Point E E = (1.42,1.52) Point E E = (1.42,1.52) Point E E = (1.42,1.52) Point F F = (4.42,1.52) Point F F = (4.42,1.52) Point F F = (4.42,1.52) Point G G = (5.7,3.38) Point G G = (5.7,3.38) Point G G = (5.7,3.38) y text1 = “y” x text1_1 = “x” 88â° text1_2 = “88â°”

Image of Triangles EFA and FGB

Showing an image of triangles EFA and FGB, so find 2y –x.


Choice (4) Response