IFS (Forests Services) Physics (Mains): Questions 16 - 20 of 34

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Question number: 16

» Special Relativity, Waves & Geometrical Optics » Geometrical Optics » System of Two Thin Lenses

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Appeared in Year: 2010

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Consider a system of two thin lenses of focal lengths and separated by a distance of in air. For an object of height placed at a distance of in front of the convex lens, find the size and position of the image. (Section A)

Explanation

  • Image from first lens is given as,

  • Now, the distance between lenses is , therefore for second lens image of first lens becomes object of second lens;

  • So, for second lens,

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Question number: 17

» Classical Mechanics » System of Particles » Constraints

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Appeared in Year: 2010

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How can one introduce the constraints of motion through the concept of generalized coordinate systems? Write down the set of transformation equations for a system of particles relating the generalized coordinates with real coordinates. (Section A)

Explanation

  • In mechanics, mostly problems can be reduced by solving differential equation, which consist of all the forces acting on a system. A such equation is given by,

  • As we know, all mechanical systems have constraint force acting on them to some degree. A constrain in which the equations connecting the coordin

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Question number: 18

» Physical Optics » Polarisation and Modern Optics » Principles of Fibre Optics Attenuation

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Appeared in Year: 2010

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With a suitable diagram, deduce an expression for numerical aperture (NA) for ab optical fiber having refractive indices of core and cladding and , respectively and being placed in a medium of index . (Section – A)

Explanation

Quadrilateral poly1Quadrilateral poly1: Polygon A, B, C, DQuadrilateral poly2Quadrilateral poly2: Polygon D, E, F, CQuadrilateral poly3Quadrilateral poly3: Polygon E, F, G, HAngle αAngle α: Angle between W, Z, IAngle βAngle β: Angle between Z, A_1, C_1Angle γAngle γ: Angle between A_1, Z, JSegment aSegment a: Segment [A, B] of Quadrilateral poly1Segment bSegment b: Segment [B, C] of Quadrilateral poly1Segment cSegment c: Segment [C, D] of Quadrilateral poly1Segment dSegment d: Segment [D, A] of Quadrilateral poly1Segment d_1Segment d_1: Segment [D, E] of Quadrilateral poly2Segment eSegment e: Segment [E, F] of Quadrilateral poly2Segment fSegment f: Segment [F, C] of Quadrilateral poly2Segment c_1Segment c_1: Segment [C, D] of Quadrilateral poly2Segment e_1Segment e_1: Segment [E, F] of Quadrilateral poly3Segment f_1Segment f_1: Segment [F, G] of Quadrilateral poly3Segment gSegment g: Segment [G, H] of Quadrilateral poly3Segment hSegment h: Segment [H, E] of Quadrilateral poly3Segment iSegment i: Segment [I, J] Segment jSegment j: Segment [K, L] Segment mSegment m: Segment [M, N] of Quadrilateral poly4Segment nSegment n: Segment [N, O] of Quadrilateral poly4Segment oSegment o: Segment [O, P] of Quadrilateral poly4Segment pSegment p: Segment [P, M] of Quadrilateral poly4Segment qSegment q: Segment [Q, R] of Quadrilateral poly5Segment rSegment r: Segment [R, S] of Quadrilateral poly5Segment sSegment s: Segment [S, M] of Quadrilateral poly5Segment m_1Segment m_1: Segment [M, Q] of Quadrilateral poly5Segment p_1Segment p_1: Segment [P, T] of Quadrilateral poly6Segment tSegment t: Segment [T, U] of Quadrilateral poly6Segment uSegment u: Segment [U, V] of Quadrilateral poly6Segment kSegment k: Segment [W, Z] Segment kSegment k: Segment [W, Z] Segment kSegment k: Segment [W, Z] Segment lSegment l: Segment [Z, A_1] Segment lSegment l: Segment [Z, A_1] Segment lSegment l: Segment [Z, A_1] Segment g_1Segment g_1: Segment [A_1, B_1] Segment g_1Segment g_1: Segment [A_1, B_1] Segment g_1Segment g_1: Segment [A_1, B_1] Segment h_1Segment h_1: Segment [A_1, C_1] Segment i_1Segment i_1: Segment [J, D_1] Point D_1D_1 = (13.78,1.04) Point D_1D_1 = (13.78,1.04) theta ‘text1 = “theta ‘”theta ‘text1 = “theta ‘”thetatext1_1 = “theta “itext1_2 = “i”Coretext1_3 = “Core”Coretext1_3 = “Core”Coretext1_3 = “Core”Coretext1_3 = “Core”Claddingtext1_4 = “Cladding”Claddingtext1_4 = “Cladding”Claddingtext1_4 = “Cladding”Claddingtext1_4 = “Cladding”Claddingtext1_4 = “Cladding”Claddingtext1_4 = “Cladding”Claddingtext1_4 = “Cladding”Claddingtext1_4 = “Cladding”Claddingtext1_5 = “Cladding”Claddingtext1_5 = “Cladding”Claddingtext1_5 = “Cladding”Claddingtext1_5 = “Cladding”Claddingtext1_5 = “Cladding”Claddingtext1_5 = “Cladding”Claddingtext1_5 = “Cladding”Claddingtext1_5 = “Cladding”n_1text1_6 = “n_1 “n_1text1_6 = “n_1 “n_2text1_7 = “n_2”n_2text1_7 = “n_2”n_2text1_8 = “n_2”n_2text1_8 = “n_2”n_0text1_9 = “n_0”n_0text1_9 = “n_0”n_2text1_ {10} = “n_2”n_2text1_ {10} = “n_2”n_1text1_ {11} = “n_1 “n_1text1_ {11} = “n_1 “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “(theta ‘=90degree-theta)text1_ {12} = ” (theta ‘=90degree-theta) “

A Light Incident in Fiber

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Question number: 19

» Physical Optics » Polarisation and Modern Optics » Principles of Fibre Optics Attenuation

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Appeared in Year: 2010

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Between multimode and single mode fibers, explain critically how and why single mode fiber is chosen for communication. (Section – A)

Question number: 20

» Physical Optics » Polarisation and Modern Optics » Single Mode Fibres

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Appeared in Year: 2010

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Why are the two wavelengths and important in single – mode fiber – optical communication system? (Section – A)

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