Electromagnetic Theory-Energy and Momentum of Electromagnetic Waves (GATE Physics): Questions 1 - 3 of 4

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Question number: 1

» Electromagnetic Theory » Energy and Momentum of Electromagnetic Waves

Appeared in Year: 2014

Short Answer Question▾

Write in Short

The intensity of a laser in free space is 150mWm2 . The corresponding amplitude of the electric field of the laser is _Vm . (ε0=8.854×1012C2Nm2)

Question number: 2

» Electromagnetic Theory » Energy and Momentum of Electromagnetic Waves

Appeared in Year: 2012

MCQ▾

Question

The space – time dependence of the electric field of a linearly polarized light in free space is given by x^E0cos(ωtkz) where E0,ω and k are the amplitude, the angular frequency and the wavevector, respectively. The time average energy density associated with the electric field is –

Choices

Choice (4) Response

a.

2ε0E02

b.

12ε0E02

c.

ε0E02

d.

14ε0E02

Question number: 3

» Electromagnetic Theory » Energy and Momentum of Electromagnetic Waves

Appeared in Year: 2010

MCQ▾

Question

Two magnetic dipole of magnitude m each are placed in a plane as shown. The energy of interaction is given by –

Angle α Angle α: Angle between A, B, CAngle β Angle β: Angle between B, C, ASegment f Segment f: Segment [A, B] Segment g Segment g: Segment [A, C] Segment h Segment h: Segment [C, B] Vector u Vector u: Vector [D, E] Vector u Vector u: Vector [D, E] Vector v Vector v: Vector [B, F] Vector v Vector v: Vector [B, F] Point A A = (-0.76, 4.24) Point A A = (-0.76, 4.24) 45/degree text1 = “45/degree”45/degree text1 = “45/degree”45/degree text1 = “45/degree”45/degree text1_1 = “45/degree”45/degree text1_1 = “45/degree”45/degree text1_1 = “45/degree”1 text2 = “1”2 text2_1 = “2”m text2_2 = “m”m text2_3 = “m”

Two Magnetic Dipoles

In figure two magnetic dipoles are placed.

Choices

Choice (4) Response

a.

μ04πm2d3

b.

3μ02πm2d3

c.

3μ08πm2d3

d.

Zero

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