Mathematical Methods of Physics-Solution of First Order Differential Equation Using RungeKutta Method (CSIR Physical Sciences): Questions 1 - 1 of 1

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Question number: 1

» Mathematical Methods of Physics » Solution of First Order Differential Equation Using RungeKutta Method

Appeared in Year: 2013

MCQ▾

Question

The solution of the partial differential equation,

2t2u(x,t)2x2u(x,t)=0

Satisfying the boundary conditions u(0,t)=0=u(L,t) and initial conditions u(x,0)=sin(πxL) and tu(x,t) t=0=sin(2πxL) is – (June)

Choices

Choice (4) Response
a.

sin(πxL)cos(2πtL)+Lπsin(2πxL)sin(πtL)

b.

sin(πxL)cos(πtL)+L2πsin(2πxL)sin(2πtL)

c.

sin(πxL)cos(πxL)+L2πsin(2πxL)cos(2πtL)

d.

2sin(πxL)cos(πtL)sin(πxL)cos(2πtL)

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