Sequence and Series-Sum Upto N Terms of Special Series (BITSAT Mathematics): Questions 1 - 4 of 4

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Question number: 1

» Sequence and Series » Sum Upto N Terms of Special Series

MCQ▾

Question

(6666)2ndigits+8888ndigit is equal to –

Choices

Choice (4) Response
a.

49(10n1)

b.

49(102n1)

c.

49(10n1)2

d. None of the above

Question number: 2

» Sequence and Series » Sum Upto N Terms of Special Series

MCQ▾

Question

If 3+14(3+d)+142(3+2d)++=8 , then value of d is –

Choices

Choice (4) Response
a.

5

b.

1

c.

9

d. None of the above

Question number: 3

» Sequence and Series » Sum Upto N Terms of Special Series

MCQ▾

Question

The sum of 40 terms of an A. P. whose first term is 2 and common difference 4, will be

Choices

Choice (4) Response
a.

3200

b.

200

c.

1600

d.

2800

Question number: 4

» Sequence and Series » Sum Upto N Terms of Special Series

MCQ▾

Question

113+123+133++203 is –

Choices

Choice (4) Response
a.

An odd integer but not a multiple of 5

b.

An odd integer devisable by 5

c.

Multiple of 10

d.

An even integer

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