Permutations and Combinations (BITSAT Mathematics): Questions 7 - 13 of 13

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Question number: 7

» Permutations and Combinations » Simple Applications

MCQ▾

Question

Equation

is equal to

Choices

Choice (4) Response

a.

Equation

b.

Equation

c.

Equation

d.

All of the above

Question number: 8

» Permutations and Combinations » Permutation as an Arrangement

MCQ▾

Question

If Equation , then the value of Equation is

Choices

Choice (4) Response

a.

2 or 6

b.

6 or 7

c.

7 or 11

d.

2 or 11

Question number: 9

» Permutations and Combinations » Combination as Selection

MCQ▾

Question

A box contains two white balls, three black balls and four red balls. The number of ways in which three balls can be drawn from the box so that one of the balls is black is –

Choices

Choice (4) Response

a.

20

b.

64

c.

84

d.

74

Question number: 10

» Permutations and Combinations » Simple Applications

MCQ▾

Question

The value of expression

Equation

is equal to –

Choices

Choice (4) Response

a.

Equation Equation

b.

Equation

c.

Equation

d.

Equation

Question number: 11

» Permutations and Combinations » Fundamental Principle of Counting

MCQ▾

Question

There are Equation copies of each Equation different books in library. The number of ways in which one or more than one book can be selected as –

Choices

Choice (4) Response

a.

Equation

b.

Equation

c.

Equation

d.

Equation

Question number: 12

» Permutations and Combinations » Fundamental Principle of Counting

MCQ▾

Question

The number of ways in which one or more balls can be selected out of 10 white, 9 green and 7 blue balls, is –

Choices

Choice (4) Response

a.

881

b.

892

c.

879

d.

891

Question number: 13

» Permutations and Combinations » Simple Applications

MCQ▾

Question

The number of all 3 elements subsets of Equation which contains Equation is –

Choices

Choice (4) Response

a.

Equation

b.

Equation

c.

Equation

d.

All of the above

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