Permutations and Combinations (BITSAT Mathematics): Questions 1  7 of 13
Get 1 year subscription: Access detailed explanations (illustrated with images and videos) to 378 questions. Access all new questions we will add tracking exampattern and syllabus changes. View Sample Explanation or View Features.
Rs. 250.00 or
Question number: 1
» Permutations and Combinations » Fundamental Principle of Counting
Question
There are white and black balls. The number of ways in which we can arrange these balls in a row so that neighboring balls are of different colors is –
Choices
Choice (4)  Response  

a. 


b. 


c. 


d. 


Question number: 2
» Permutations and Combinations » Simple Applications
Question
The number of ways in which students can be distributed equally among sections is –
Choices
Choice (4)  Response  

a. 


b. 


c. 


d. 


Question number: 3
» Permutations and Combinations » Meaning of P (N,R) and C (N,R)
Question
If , then value of is –
Choices
Choice (4)  Response  

a.  7 

b.  4 

c.  5 

d.  6 

Question number: 4
» Permutations and Combinations » Combination as Selection
Question
If points out of 12 are in same straight line, then the number if triangles formed is
Choices
Choice (4)  Response  

a.  19 

b.  201 

c.  185 

d.  508 

Question number: 5
» Permutations and Combinations » Simple Applications
Question
If is an even positive integer they , is maximum where ,
Choices
Choice (4)  Response  

a.  n 

b.  0 

c. 


d.  Question does not provide sufficient data or is vague 

Question number: 6
» Permutations and Combinations » Simple Applications
Question
A parallelogram is cut by two sets of parallel lines parallel to the sides of the parallelogram. The number of parallelogram thus formed is –
Choices
Choice (4)  Response  

a. 


b. 


c. 


d.  Question does not provide sufficient data or is vague 

Question number: 7
» Permutations and Combinations » Simple Applications
Question
is equal to
Choices
Choice (4)  Response  

a. 


b. 


c. 


d.  All of the above 
