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Answer :

`(y-1)^(2)=4(x+1),"Vertex"-=(-1,1)`Solution :

From the definition of parabola, any point on the parabola P(x,y) is equidistant from focus and directrix. <br> `So," "(x-0)^(2)+(y-1)^(2)=((x+2)/(sqrt(1)))^(2)` <br> `or" "(y-1)^(2)=4(x+1)` <br> Thus, vertex of parabola is (-1,1).