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Solution :

Radius of the roller, `r = 42 cm`, and its length, `h = 120 cm` <br> Area covered by the roller in `1` revolution <br> = curved surface area of the roller <br> `= (2pi rh)` sq units <br> `= (2 xx (22)/(7) xx 42 xx 120) cm^(2) = 31680 cm^(2)` <br> Area covered by the roller in 500 revolutions <br> `(31680 xx 500) cm^(2) = ((31680 xx 500)/(100 xx 100)) m^(2) = 1584 m^(2)` <br> `:.` area of the playground `= 1584 m^(2)` <br> Cost of levelling the playground `= Rs (1584 xx 5) = Rs 7920`