Atoms and Nuclei-Nuclear Fission and Fusion (AIIMS Physics): Questions 1 - 5 of 7

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Question number: 1

» Atoms and Nuclei » Nuclear Fission and Fusion

Appeared in Year: 2006

MCQ▾

Question

The operation of a nuclear reactor is said to be critical, if the multiplication factor (k) has a value –

Choices

Choice (4) Response

a.

2.1

b.

1.5

c.

2.5

d.

1

Question number: 2

» Atoms and Nuclei » Nuclear Fission and Fusion

Appeared in Year: 2003

MCQ▾

Question

Nuclear fusion is possible –

Choices

Choice (4) Response

a.

only between light nuclei.

b.

only between nuclei which are stable against β -decay.

c.

between both light and heavy nuclei.

d.

only between heavy nuclei.

Question number: 3

» Atoms and Nuclei » Nuclear Fission and Fusion

Appeared in Year: 2004

Assertion-Reason▾

Assertion (Ꭺ)

Energy is released in nuclear fission.

Reason (Ꭱ)

Total binding energy of the fission fragments is larger than the total binding energy of the parent nucleus

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

b.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ

c.

Ꭺ is true but Ꭱ is false

d.

Both Ꭺ and Ꭱ are false

Question number: 4

» Atoms and Nuclei » Nuclear Fission and Fusion

Appeared in Year: 2003

Assertion-Reason▾

Assertion (Ꭺ)

Neutrons penetrate matter more readily as compared to protons.

Reason (Ꭱ)

Neutrons slightly more massive than protons

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are false

b.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

c.

Ꭺ is false but Ꭱ is true

d.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ

Question number: 5

» Atoms and Nuclei » Nuclear Fission and Fusion

Appeared in Year: 2005

Assertion-Reason▾

Assertion (Ꭺ)

It is not possible to use 35Cl as the fuel for fusion energy.

Reason (Ꭱ)

The binding energy of 35Cl is too small.

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are false

b.

Ꭺ is true but Ꭱ is false

c.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

d.

Ꭺ is false but Ꭱ is true

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