Atoms and Nuclei-Binding Energy Per Nucleon (AIIMS Physics): Questions 1 - 3 of 4

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Question number: 1

» Atoms and Nuclei » Binding Energy Per Nucleon

Appeared in Year: 2004

MCQ▾

Question

The dependence of binding energy per nucleon (BN) on the mass number (A), is represented by

Choices

Choice (4) Response

a.

Graph of Binding energy v/s mass number: Choice - A

Graph of Binding Energy v/s Mass Number: Choice - a

In figure graph represent the dependence of binding energy per nucleon on the mass number.

b.

Graph of Binding energy v/s mass number: Choice - B

Graph of Binding Energy v/s Mass Number: Choice - B

In figure graph represent the dependence of binding energy per nucleon on the mass number.

c.

Graph of Binding energy v/s mass number: Choice - C

Graph of Binding Energy v/s Mass Number: Choice - C

In figure graph represent the dependence of binding energy per nucleon on the mass number.

d.

Graph of Binding energy v/s mass number: Choice - D

Graph of Binding Energy v/s Mass Number: Choice - D

In figure graph represent the dependence of binding energy per nucleon on the mass number.

Question number: 2

» Atoms and Nuclei » Binding Energy Per Nucleon

Appeared in Year: 2004

Assertion-Reason▾

Assertion (Ꭺ)

Nuclear binding energy per nucleon is in the order

Reason (Ꭱ)

Binding energy per nuclear increases linearly with difference in number of neutrons and protons.

Choices

Choice (4) Response

a.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

b.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ

c.

Ꭺ is false but Ꭱ is true

d.

Both Ꭺ and Ꭱ are false

Question number: 3

» Atoms and Nuclei » Binding Energy Per Nucleon

Appeared in Year: 2006

Assertion-Reason▾

Assertion (Ꭺ)

The binding energy per nucleon, for nuclei with atomic mass number A>100 , decreases with A.

Reason (Ꭱ)

The nuclear forces are weak for heavier nuclei.

Choices

Choice (4) Response

a.

Ꭺ is true but Ꭱ is false

b.

Both Ꭺ and Ꭱ are true but Ꭱ is NOT the correct explanation of Ꭺ

c.

Both Ꭺ and Ꭱ are true and Ꭱ is the correct explanation of Ꭺ

d.

Ꭺ is false but Ꭱ is true

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