AIIMS (All India Institute of Medical Sciences) Physics: Questions 342 - 346 of 500

Visit this page to view all the question topics

To view these problems with solutions proceed here and click "Subscribe Now".

Question number: 342

» Oscillations and Waves » Periodic Functions

MCQ▾

Question

In an experiment, on the measurement of , by a simple pendulum, the time period was measured with an accuracy of 0.1 % and the length was measured with an accuracy of . The resultant value of obtained with accuracy . Than find the value of .

Choices

Choice (4) Response

a.

b.

c.

d.

To view these problems with solutions proceed here and click "Subscribe Now".

Question number: 343

» Electromagnetic Induction & Alternating Currents » Induced EMF and Current

MCQ▾

Question

A conducting ring of radius 2 meter is placed in a uniform magnetic field B of 0.04 T, oscillating with frequency 500 Hz with its plane at right angles to magnetic field. What will be the induced electric field?

Choices

Choice (4) Response

a.

b.

c.

d.

To view these problems with solutions proceed here and click "Subscribe Now".

Question number: 344

» Atoms and Nuclei » Radioactive Decay Law

MCQ▾

Question

A radioactive material has a half – life of 9 days. What fraction of the material would remain after 45 days –

Choices

Choice (4) Response

a.

0.03125

b.

0.625

c.

0.125

d.

0.0156

To view these problems with solutions proceed here and click "Subscribe Now".

Question number: 345

» Electronic Devices » Junction Transistor

MCQ▾

Question

In an NPN transistor amplifier for common – emitter configuration, the current gain of the transistor is 160 and the collector current changes by 0.8 mA, so find the change in emitter current.

Choices

Choice (4) Response

a.

1.805mA

b.

0.08 mA

c.

1.8 mA

d.

0.805 mA

To view these problems with solutions proceed here and click "Subscribe Now".

Question number: 346

» Work, Energy and Power » Work-Energy Theorem

MCQ▾

Question

Ratio of mass of proton and mass of electron is nearly about 1840. Now, if proton is accelerated by a potential difference of 2 KV, its kinetic energy is –

Choices

Choice (4) Response

a.

b.

c.

d.

To view these problems with solutions proceed here and click "Subscribe Now".